Question

$sqrt{3x+7} =x-7$

Answer 1

ОДз
{3x+7≥0⇒x≥-7/3
{x-7≥0⇒x≥7
x∈[7;∞)
3x+7=x²-14x+49
x²-17x+42=0
x1+x2=17 U x1*x2=42
x1=3∉ОДЗ
x=14