Question

log2(x-y)=1 и 2x3y+1=72 помогите

Answer 1

x-y=2
x=2+y
2(2+y)*3y+1=72
6y²+12y-71=0
D=144+1704=1848
y1=(-12-2√462)/12=-1-1/6*√462
x1=1-1/6*√462
y2=-1+1/6*√462
x2=1+1/6*√462