Question

решите уравнение 2sin8x-корень из 2=0

Answer 1

2sin8x-√2=0
2sin8x=√2
sin8x=(√2)/2
a)8x=π/4+2k.π
     x=π/32+k.π/4, k∈Z
b)8x=3π/4+2k.π
     x=3π/24+k.π/4, k∈Z

(sinπ/4=sin3π/4=√2/2)
(sinx=sin(x+2kπ))

Answer 2

b)x=3pí/32+k.pí/4