Question

помогите третье задание

Answer 1

$left { {{6^{x}-2cdot 3^{y}=2} atop {6^{x}cdot 3^{y}=12}} right. ; ;quad u=6^{x}; ;; v=3^{y};quad left { {{u-2v=2} atop {uv=12}} right. \\ left { {{u=2+2v} atop {2v^2+2v-12=0}} right. \\v^2+v-6=0; ; to ; ; v_1=2; ,; v_2=-3\\1)quad v=3^{y}=2; ,; ; y=log_32\\v=2; ; to ; ; u=2+2cdot 2=6; ,; 6^{x}=6; to ; ; x=1\\2)quad v=3^{y}=-3; ; net; ; reshenij,; t.k.; ; 3^{y} textgreater 0\\Otvet:; ; (1;, log_32).$