Question

lim(x-> 0)sin ^2 5x/(cos(4x)* tg(x)) =

Answer 1

$lim_{x to 0} frac{sin^25x}{cos4x cdot tgx} = lim_{x to 0} frac{25x^2}{xcdot cos4x} = lim_{x to 0} frac{25x}{cos 4x} =0$