Question

найдите значение выражения 36-у^2/у^2-12у+36 при у=3/4

Answer 1

(6-y)(6+y)/(6-y)²=(6+y)/(6-y)
y=3/4
6 3/4: 5 1/4=27/4*4/21=9/7=1 2/7

Answer 2

y²-12y+36=(y-6)²=(6-y)²
(6-y)(6+y)/(6-y)² = 6+y/6-y
y=3/4  6+3/4=27/4   6-3/4=21/4
27/4 * 4/21= 27/21=9/7