Question

Пожалуйста помогите
[(9k^2-m^2)/k] * [(k/(3k+m) - k/m)]

Answer 1

$frac{9 k^{2} - m^{2} }{k}$ ·$( frac{k}{3k+m} - frac{k}{m} )$=
9k²-m² · $( frac{1}{3k+m} - frac{1}{m} )$=$frac{(3k+m)(3k-m)(m-(3k+m))}{m(3k+m)}$ = $frac{-3k(3k-m)}{m}$