Question

Найти f'(1/3), если f(x) =x(x-1)2

Answer 1

$f(x)=x(x-1)^2\f'(x)=(x-1)^2+2x(x-1)\f'(frac{1}3)=(frac{1}3-1)^2+frac{2}3(frac{1}3-1)=(-frac{2}3)^2-frac{2}3*frac{2}3=0$