Question

Помогите решить Sin^2x+2sinx*cosx=0,25-cos(pi/2+2x)

Answer 1

sin²x+2sinx*cosx=0,25+sin2x
sin²x=0,25
(1-cos2x)/2=1/4
1-cos2x=1/2
cos2x=1/2
2x=+-π/3+2πk,k∈z
x=+-π/6+πk,k∈z