Question

с поянением пожалуйста 8 номер

Answer 1

$left{begin{array}{c}5x+12leq3x+7,\x textless 2x+3,\2x+7geq0;end{array}right. left{begin{array}{c}5x-3xleq7-12,\x-2x textless 3,\2xgeq-7;end{array}right. left{begin{array}{c}2xleq-5,\-x textless 3,\xgeq-3,5;end{array}right. \ left{begin{array}{c}xleq-2,5,\x textgreater -3,\xgeq-3,5;end{array}right. left { {{xleq-2,5, atop {x textgreater -3;} right. \ xin(-3;-2,5]$