Question

2х2-32<0,
3x-12>4-5x Решения неравенства

Answer 1

2x^2-32<0,

2(x^2-16)<0,

x^2-16<0,

(x+4)(x-4)<0,

(x+4)(x-4)=0,

x1=-4, x2=4,

-4<x<4;

 

3x-12>4-5x,

3x+5x>4+12,

8x>16,

x>2.

Answer 2

2х^2<32

x^2<16

-4<x<4

 

3x-12>4-5x

3x+5x>4+12

8x>16

x>2