Question

y=корень2x дифференциал

Answer 1

$y = sqrt{2x} ;$

$dy = d(2x)^{1/2} = frac{1}{2} (2x)^{1/2-1} dx = frac{1}{2} (2x)^{-1/2} dx = frac{dx}{ 2 (2x)^{1/2} } = frac{dx}{ 2 sqrt{2x} } .$