Question

решите неравенство:2x^2-8x/x-7<=x

Answer 1

(2x²-8x)/(x-7)-x≤0
(2x²-8x-x²+7x)/(x-7)≤0
(x²-x)/(x-7)≤0
x(x-1)/(x-7)≤0
x=0
x=1
x=7
            _                +                  _               +
---------------[0]-----------[1]---------------(7)----------------
x∈(-∞;0] U [1;7)