Предмет: Физика, автор: zshvec

Помогите решить задачу
Оствляет ли женщина, которая носит шпильки, вмятины на асфальте, если поверхность асфальта выдерживает авление 1 МПа?Площадь шпильки составляет 1 см^2,масса женщины 50 кг,на одну шпильку действует 1/4 масса женщины

Ответы

Автор ответа: vovkaZZ

0

p=Fдав/S=mg/s

Переводим площадь в м2
1см^2=0.0001м^2 и умножаем на 2 т.к. две шпильки
1/4 от массы женщины это 12,5кг и умножаем на 2 т.к. две шпильки

Подставляем в формулу:
$frac{25*10}{0,0002}$ = 1250000Па=1,25МПа
Следовательно 1,25МПа>1МПА
Значит женщина оставит вмятины на асфальте

Автор ответа: zshvec

0

Огромное спасибо

Автор ответа: zshvec

0

Можно к вам еще обращаться подробнося все очень

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