Question

решите уравнение
 10/25 -х² - 1/5+х - х/х-5=0 

Answer 1

$10/(25 -x^2)-1/(5+x)-x/(x-5)=0<var></var>$ | * $(x-5)(x+5) = (x^2-25)$

 

$-10/(x^2 - 25) - 1/(5+x) - x/(x-5)=0<var></var>$ | * $(x-5)(x+5) = (x^2-25)$

 

 

$-10 - (x-5) - x(x+5) = 0\ -10 -x + 5 -x^2 - 5x = 0\ -5 -6x - x^2 = 0\ x^2 + 6x + 5 = 0\ (x + 1)(x + 5) = 0\ x_1 = -1, x_2 = -5\ x_2 = -5,$

не подходит.

 

$<var></var>x = -1$