Question

sin2a/2cosa; sin2a/sina; 3cos^a/sin2a; cos2a/sina+cosa пж)))

Answer 1

$frac{sin2alpha}{2cosalpha}=frac{2sinalpha*cosalpha}{2cosalpha}=sinalpha$

$frac{sin2alpha}{sinalpha}=frac{2sinalpha*cosalpha}{sinalpha}=2cosalpha$

$frac{3cos^2alpha}{sin2alpha}=frac{3cosalpha*cosalpha}{2sinalpha*cosalpha}=frac{3cosalpha}{2sinalpha}=1.5tgalpha$

$frac{cos2alpha}{sinalpha+cosalpha}=frac{cos^2alpha-sin^2alpha}{sinalpha+cosalpha}=frac{(cosalpha-sinalpha)*(cosalpha+sinalpha)}{cosalpha+sinalpha}=cosalpha-sinalpha$