Question

Решите на множестве RxR методом подстановки :

2x-y=1

6x+2y=0

Answer 1

$left { {{2x-y=1} atop {6x+2y=0}} right. \\ left { {{y=2x-1} atop {6x+2(2x-1)=0}} right. \\ left { {{y=2x-1} atop {6x+4x-2=0}} right.\\ left { {{y=2x-1} atop {10x=2}} right. \\ left { {{y=2x-1} atop {x=0,2}} right.\\ left { {{y=2*0,2-1} atop {x=0,2} right. \\ left { {{y=0,4-1} atop {x=0,2}} right.\\ left { {{y=-0,6} atop {x=0,2}} right. \\(0,2;-0,6)$