Предмет: Химия, автор: Аноним

Используя метод электронного баланса, составьте уравнение реакции
P2H4 + HClO3 → … + Cl2 + …
Определите окислитель и восстановитель.

Ответы

Автор ответа: Аноним

0

5P2H4 + 14HClO3 = 10H3PO4 + 7Cl2 + 2H2O:

2P-2 -14e- = 2P+5 | 14 | 70 | 5 |

2Cl+5 +10e- = Cl2 | 10 | | 7 |.

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