Question

помогите!!!!! 3 4 !!! по середине

Answer 1

$frac{2-7y}{6} + frac{4y+7}{3} =- frac{y}{2} \ 2-7y+2(4y+7)=-3y \ 2-7y+8y+14+3y=0 \ 4y=-16 \ y=-4$

$frac{7y-1}{12} - frac{y+1}{4} = frac{2y+5}{3} \ 7y-1-3(y+1)=4(2y+5) \ 7y-1-3y-3=8y+20 \ 4y=-24 \ y=-6$

Answer 2

что?