Question

2sin^2(x)+2sinxcos2x-1=0

Answer 1

$2sin^{2}x+2sinxcosx-1=0\ frac{2(1-cos2x)}{2}+2sinxcosx-1=0\ 1-cos2x+2sinxcosx-1=0\ 2sinxc0s2x-cos2x=0\ cos2x(2sinx-1)=0\ cos2x=0 2sinx-1=0\ 2x=frac{pi}{2}+2pi*n 2sinx=1 sinx=frac{1}{2}\ x=frac{pi}{4}+pi*n; x=frac{pi}{6}+2pi*n; x=pi-frac{pi}{6}+2pi*n=frac{5pi}{6}+2pi*n$