Предмет: Физика, автор: Bogdan31072001

6. Тело, находящееся внутри воды, выталкивается с силой 2 Н. С какой силой это тело будет выталкиваться керосином, плотность которого – 0,8 г/см3?

Ответы

Автор ответа: nata06050605

формула архимеда= g*v(погруженной чассти тела) q(плотность жидкости)
2) подставляем значения 1000*10*V=2 н (1000-плтность воды)
V=0,0002 м3
3) подставим все эти значения, только жидкость , которую погружаем тела будет иметь плотноссть 800 кг/м3
800*10* 0.0002=F
F=1,6 Н

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