Question

помогите решить очень срочно!!!

Answer 1

∈$\left \{ {{3x-2 \geq 0 } \atop {x+2\ \textgreater \ 0}} \right. \\ \left \{ {{3x \geq 2} \atop {x\ \textgreater \ -2}} \right. \\ \left \{ {{x \geq \frac{2}{3} } \atop {x\ \textgreater \ -2}} \right. \\ Otvet: x ∈ \left[\begin{array}{ccc} \frac{2}{3} \end{array} ; +∞)$