Question

(x^2-5x)^2 + (x^2-25)^2=0

Answer 1

(x^2-5x)^2 + (x^2-25)^2=0, (x^2-5x)^2=-(x^2-25)^2, x^2-5x=-(x^2-25), x^2-5x=-x^2+25, 2x^2-5x-25=0, D=(-5)^2-4×2×(-25)=225, x1=(5-корень 225)/(2×2)=(5-15)/4=-10/4=-2,5, х2=(5+корень 225)/(2×2)=(5+15)/4=20/4=5