Question

решите уравнение.192:(5х-3)-7/9=10005/10005

Answer 1

$frac{192*9}{9(5x-3)} - frac{7(5x-3)}{9(5x-3)} - frac{9(5x-3)}{9(5x-3)} =0\ 5x-3 neq 0\ x neq frac{3}{5}\ 1728-35x+21-45x+27=0\ -80x=-1776 \ x=1776:80=22.2$