Question

Решите номер 55.Есть вложение.

Answer 1

$cfrac{11a^6b^3-(3a^2b)^3}{4a^6b^6} = cfrac{11a^6b^3-27a^6b^3}{4a^6b^6} = cfrac{-16a^6b^3}{4a^6b^6} = -cfrac{4}{b^3} = -cfrac{4}{2^3} =-cfrac{4}{8} =-0.5$