Question

Решите уравнение:
(3х+1)²-6х=3

Answer 1

(3х+1)²-6х=3

(a+b)²=a²+2ab+b²
(3х+1)²=3²x²+2*3x*1+1²=9x²+6x+1

9x²+6x+1-6x=3
9x²+1=3
9x²=3-1
9x²=2
$x^{2} = frac{2}{9} \ x=pm sqrt{ frac{2}{9}} \ x=pmfrac{ sqrt{ 2}}{ sqrt{ 9} } \ x=pm frac{ sqrt{2} }{3}$