Question

Решите плиз с;
$10 x^{2} -12x+1=-10 x^{2}$

Answer 1

20x^2 - 12x + 1 = 0 
D = 144 - 80 = 64
x1 = ( 12 + 8)/40 = 20/40 = 1/2 = 0,5
x2 = ( 12 - 8)/40 = 4/40 = 1/10 = 0,1 

Answer 2

$20x^2-12x+1=0;\2xcdot10x-10x-2x+1=(10x-1)(2x-1)=0;;x=1/10;;x=0.5$