Question

Помогите решить 27.10
Заранее спасибо ^_^

Answer 1

(2a+3b)(4a²-6ab+9b²)=8a³-12a²b+18ab²+12a²b-18ab²+27b³ = 8a³+27b³

 

(5-2a+a²)(4a²-3a-1)=20a²-15a-5-8a³+6a²+2a+4a⁴-3a³-a² = 4a⁴-11a³+25a²-13a-5

 

 

 

 

 

Answer 2

27.10) $(2a+3b)(4a^{2}-6ab+9b^{2})=8a^{3}+27b^{3} (5-2a+a^{2})(4a^{2}-3a-1)=22a^{2}-13a-5-6a^{3}+4a^{4} (5x-2y)(25x^{2}+10xy+4y^{2})=125x^{3}-8y^{3} (m^{2}-m+2)(3m^{2}+m-2)=3m^{4}-2m^{3}+3m^{2}+4m-4$