Предмет: Химия, автор: nastyamuuuuuur

Найдите массу сульфата бария, полученного при взаимодействии раствора, содержащего 0,7 моль хлорида бария с избытком серной кислоты.

Ответы

Автор ответа: zefa2013

Хг 0,7моль
BaSO4 + 2HCl = BaCl2 + H2SO4
233г 1 моль

х = 233г * 0,7 моль/ 1 моль = 163,1г))))

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