Question

6х(2х-1)-7х=
2 (5х-4у+1)-3 (3х-3у+1)=
а+b+c-(a-b-c)=
7 (2a+5b)-5 (3b-4a)=
8 (3x-2y)-7 (y+x)=
-2 (a-3b)+3 (b-2a)

Answer 1

12$x^{2}$-6х-7х=12$x^{2}$-13x
a+b+c-a+b+c=2b+2c
14a+25b-15b+20a=34a+10b
24x-16y-7y-7x=17x-23y
-2a+6b+3b-6a=-8a+9b