Question

log0,5(4x-1)-log0,5(7x-3)=1

Answer 1

{4x-1>0⇒x>0,25
{7x-3>0⇒x>3/7
x∈(3/7;∞)
log(0,5)[(4x-1)/(7x-3)]=1
(4x-1)/(7x-3)=1/2
2(4x-1)=7x-3
8x-7x=-3+2
x=-1 не удов усл
нет решения