Question

решите пожалуйста (6) завтра контрольная заранее спасибо

Answer 1

$2sqrt{6+2sqrt{5-sqrt{13+sqrt{48}}}} = 2sqrt{6+2sqrt{5-sqrt{1+sqrt{4cdot12}+12}}} =\= 2sqrt{6+2sqrt{5-sqrt{1^2+2sqrt{12}+(sqrt{12})^2}}} =\= 2sqrt{6+2sqrt{5-sqrt{(1+sqrt{12})^2}}} = 2sqrt{6+2sqrt{5-(1+sqrt{12})}} =\= 2sqrt{6+2sqrt{4-sqrt{12}}} = 2sqrt{6+2sqrt{1-sqrt{4cdot3}+3}} =\= 2sqrt{6+2sqrt{1^2-2sqrt{3}+(sqrt{3})^2}} = 2sqrt{6+2sqrt{(1-sqrt{3})^2}}} =\= 2sqrt{6+2|1-sqrt{3}|} = 2sqrt{6+2(sqrt{3}-1)} = 2sqrt{4+2sqrt{3}} =$
$=2sqrt{1+2sqrt{3}+3} = 2sqrt{1^2+2sqrt{3}+(sqrt{3})^2} = 2sqrt{(1+sqrt{3})^2} =\= 2(1+sqrt{3}) = 2+2sqrt{3}$