Question

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Answer 1

2x^2-3x+3-3+x^2=0

3x^2-3x=0

x^2-x=0  x=1 x=0

F(x)=3(x^3/3-x^2/2)=x^3-3x^2/2

F(0)=0

F(1)=-3/2

S=3/2

2x^2-x-2x-2=0

2x^2-3x-2=0

F(x)=2x^3/3-3x^2/2-2x

F(-1/2)=13/24

F(2)=16/3-6-4=16/3-10

S=115/24=4 19/24