Question

$sqrt{3} tg(frac{3x}{4}+frac{pi}{6})=1$

Answer 1

$sqrt{3}tg(frac{3x}{4}+frac{pi}{6})=1;\ tg(frac{3x}{4}+frac{pi}{6})=frac{1}{sqrt{3}};\ frac{3x}{4}+frac{pi}{6}=frac{pi}{6}+pi*k;\ frac{3x}{4}=pi*k;\ x=frac{4*pi*k}{3};$

k є Z