Question

3(3х-1)+12=х решите плз

Answer 1

$3(3x-1)+12=x \ 9x-3+12-x=0 \ 8x+9=0 \ 8x=-9 \ x=- frac{9}{8}=-1 frac{1}{8}=-1.125$

Answer 2

3(2х-1)+12=х

Answer 3

6x-3+12-x=0
5x=-9
x=-1 4/5=-1.8

Answer 4

9х-3+12=х
9х-х=3-12
8х=-9
Х=-9/8