Question

sin (pi/2+2x) + cos (pi/2 -2x)= 0

Answer 1

sin pi/2cos2x+ cos pi/2 sin 2x +cos pi/2 cos 2x + sin pi/2 sin 2x = 0

cos 2x +0 + 0 + sin 2x = 0

cos 2x = -sin 2x

tg x = -1

x = (-pi/4) + 2pi n