Question

(3цел 1/4 + 1цел 1/6 : 1цел 5/9) : 2цел 2/7 + 5цел 1/9 :7цел 2/3

Answer 1

$(3frac{1}{4}+1frac{1}{6}/1frac{5}{9})/2frac{2}{7}+5frac{1}{9}/7frac{2}{3} = (frac{13}{4}+frac{7}{6}/frac{14}{9})/frac{16}{7}+frac{46}{9}/frac{23}{3} = (frac{13}{4}+frac{7}{6}*frac{9}{14})*frac{7}{16}+frac{46}{9}*frac{3}{23} = (frac{13}{4}+frac{3}{4})*frac{7}{16}+frac{2}{3} = frac{16}{4}*frac{7}{16}+frac{2}{3} = frac{7}{4}+frac{2}{3} = frac{21}{12}+frac{8}{12} = frac{29}{12} = 2frac{5}{12}$