Question

2+3tg^2x, если соs^2x=0.6

Answer 1

$cos^2x=0.6 \ 2+3tg^2x= frac{3sin^2x}{cos^2x}+2= frac{3-3cos^2x}{cos^2x} +2= \ \ = frac{3-3*0.6}{0.6}+2 = frac{3-1.8}{0.6}+2= frac{1.2}{0.6}+2=2+2=4$