Question

2.Упростите выражение.(8х в квадрате+13х-6):(х+2), при х=6,125

Answer 1

$\frac{8x^2+13x-6}{x+2}=\frac{8(x+2)(x-\frac{3}{8})}{x+2}=8(x-\frac{3}{8})=8x-3=8\cdot 6,125-3=46\\\\\\8x^2+13x-6=0\\\\D=169+192=361\\\\x_1=\frac{-13-19}{16}=-2,\; \; x_2=\frac{-13+19}{16}=\frac{3}{8}\; \to \\\\8x^2+13x-6=8(x+2)(x-\frac{3}{8})$