Question

√(6+4√2) + √(6-4√2)-решить

Answer 1

$\sqrt{6+4 \sqrt{2} } + \sqrt{6-4 \sqrt{2} } =z \\ |()^2 \\ 6+4 \sqrt{2} +6-4 \sqrt{2}+2 \sqrt{(6+4 \sqrt{2})(6-4 \sqrt{2}) }=z^2 \\ 12+2 \sqrt{36-32} =z^2 \\ z^2=12+2* \sqrt{4}=12+2*2=12+4=16 \\ z^2=16 \\ z= \sqrt{16}=4 \\ z=4$