Question

pajalusta naydite eta zadachaaaaaassssw

Answer 1

        $log_{ 24sinx } 24cosx = \frac{3}{2}\\ 24cosx = (24sinx)^{\frac{3}{2}} \\ 24cosx = 24\sqrt{24} * (sinx) ^{\frac{3}{2}} \\ cosx=\sqrt{24}*(sinx)^{\frac{3}{2}} \\ t= \sqrt{24} * (\sqrt{1-t^2})^{\frac{3}{2}} \\ t^2=24*\sqrt{1-t^2}^3 \\ \frac{t^2}{ (1-t^2 ) ^ {\frac{3}{2}}}=24 \\ t^2=y\\ \frac{y}{(1-y)^{\frac{3}{2}}} = 24 \\ \frac{y^2}{(1-y)^3}=24^2 \\ y^2 = 576(1-y)^3 \\ (9y-8)(64*y^2-135y+72)=0\\ y=\frac{8}{9}\\ ctg^2x=8$  
   
   
    $24*8 = 192$