Question

(3а-2)в квадрате -2(а-2)(а-3)+ (2а-1)(2а+1).

Answer 1

$\\(3a-2)^2 - 2(a-2)(a-3)+(2a-1)(2a+1) =\\ = 9a^2 -12a +4 -2*(a^2-3a -2a +6) + 4a^2 -1 = \\ =13a^2 - 12a +3 -2a^2+5a -12 = 11a^2 -7a -9$