Question

найдите значения выражения 3cos (P-B)+sin (P/2+B)/cos(B+3P)=

Answer 1

(3cos(π -β)+sin(π/2 +β))/cos(3π+β)  =( -3cosβ +cosβ)/(-cosβ) = (-2cosβ)/(-cosβ) =2.

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3cos(π -β)+sin(π/2 +β)/cos(3π+β)  = -3cosβ +cosβ)/(-cosβ) = - 3cosβ -1 .