Question

(3x-5)/2)+(8x-12)/7)=9

Answer 1

3х-5/2 + 8x-12/7=9   

21x-35+16x-24=126

37x=126+35+24

37x=185

x=5

Answer 2

21x-35+16x-24=126 37x-59=126 37x=185 x=5

Answer 3

Решение:

$displaystyle [begin{gathered}frac{{3x-5}}{2}+frac{{8x-12}}{7}=9hfill\frac{{7(3x-5)}}{{2*7}}+frac{{2(8x-12)}}{{7*2}}=9hfill\frac{{21x-35}}{{14}}+frac{{16x-24}}{{14}}=9hfill\frac{{21x-35+16x-24}}{{14}}=9hfill\frac{{37x-59}}{{14}}=9hfill\37x-59=9*14hfill\37x-59=126hfill\37x=126+59hfill\37x=185hfill\x=185:37hfill\x=5hfill\end{gathered}]$