Предмет: Геометрия, автор: Matan111

Вычислите объем конуса, радиус основания которого 24 дм, а площадь его осевого сечения 168 дм².

Ответы

Автор ответа: masha12345612

Диаметр основания будет = 2*24
Теперь нужно расписать площадь. Получается
168=1/2*24*2*h
h=7
Формула объема конуса:
V=1/3* $\pi$ *r^2*h
Теперь подставляем значение
V=1/3*24*24* $\pi$ *7=56*24* $\pi$ =1344 $\pi$
ответ: 1344* $\pi$

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