Question

корень из {x+3y+8}=2 корень из (2х-у+2)=1
это система

Answer 1

$\sqrt{x+3y+8}=2$
$\sqrt{2x-y+2} =1$

$x+3y+8=4$
$2x-y+2=1$

$x+3y=-4$
$2x-y=-1$

$x+3y=-4$
$6x-3y=-3$

$7x=-7$
$x+3y=-4$

$x=-1$
$y=2x+1$

$x=-1$
$y=-1$
Ответ: (-1; -1)

Answer 2

ОДЗ
$x+3y+8 \geq 0 \\ x+3y \geq -8 \\ \\ 2x-y +2 \geq 0 \\ 2x-y \geq -2$

$\left \{ { \sqrt{x+3y+8}=2 } \atop { \sqrt{2x-y+2} =1}} \right. \\ \\ \left \{ {x+3y+8=4} \atop {2x-y+2=1}} \right. \\ \\ \left \{ {{x+3y+4=0} \atop {2x-y+1=0}} \right. \\ \\ \left \{ {{x+3y+4=0} \atop {6x-3y+3=0}} \right. \\ \\ \left \{ {{7x+7=0} \atop {x+3y+4=0}} \right. \\ \\ \left \{ {{x=-1} \atop {-1+3y+4=0}} \right. \\ \\ \left \{ {{y=-1} \atop {x=-1}} \right.$

x=-1 y=-1 подходят по ОДЗ
Ответ: -1;-1