Question

log3 1/27 + logкорень 4 степени из 8 64

Answer 1

$log_3 \frac{1}{27}+ log_{ \sqrt[4]{8} } 64=log_3 3^{-3} + log_{2^{\frac{3}{4}}} 64=-3+ \frac{4}{3}log_2 2^6=-3 + \frac{4}{3}\cdot6=\\=-3 + 8=5$