Question

Найти дифференциациал функции y=3x^2+8

Answer 1

$\displaystyle \text{d}y=\text{d}\Big(3x^2+8\Big)=\text{d}\Big(3x^2\Big)+\text{d}\Big(8\Big)=3\text{d}\Big(x^2\Big)+0=3\cdot 2x\text{d}x=\boxed{6x\text{d}x}\phantom{.}.$