Question

Lim (1/x-3 - 6/x^2-9) Найти предел
x=>3

Answer 1

$\lim_{x \to 3} \frac{x+3-6}{ x^{2} -9}= \lim_{x \to 3} \frac{x-3}{(x-3)(x+3)}= \lim_{x \to 3} \frac{1}{x+3}=1/6$