Question

Найдите производную функции
y=(x^2+3)(x^4-1)
y=(x^2-2)(x^7+4)

Answer 1

$1)y' = ((x^2+3)(x^4-1))' = (x^6+3x^4-x^2-3)' = 6x^5+12x^3-2x\\ 2)y'=((x^2-2)(x^7+4))'=(x^9-2x^7+4x^2-8)'=9x^8-14x^6+8x$